4x^2-39.8x+96.04=0

Solution for 4x^2-39.8x+96.04=0 equation:

4x^2-39.8x+96.04=0

a = 4; b = -39.8; c = +96.04;
Δ = b2-4ac
Δ = -39.82-4·4·96.04
Δ = 47.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39.8)-\sqrt{47.4}}{2*4}=\frac{39.8-\sqrt{47.4}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39.8)+\sqrt{47.4}}{2*4}=\frac{39.8+\sqrt{47.4}}{8}
$